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Saddles, Skirts and Differential Expansion — One Holds, One Lets Go

The exchanger that tore its own foundation

A 1.2 m diameter crude preheat exchanger, 6 m between saddle centres, runs at 220 °C. It was installed on a cold Sunday by a crew who were told to "bolt it down properly", and they did — both saddles, all eight M24 bolts, torqued to the same value off the same chart.

Eighteen months later the routine inspection finds a hairline crack in the grout at the east pier, two anchor bolts bent like hairpins, paint flaked off the shell at the saddle horn, and one slotted hole visibly elongated into a bright steel smear.

Guess before you read on: the vessel only moved about 15 mm. What size of force does 15 mm of blocked movement generate at that saddle — same order as the 15 kN of friction the design allowed for, or something else?

878 kN. Fifty-nine times the design number. Not because anything was overloaded in the usual sense, but because a displacement that had nowhere to go got converted into a force by the stiffness of a very good concrete pier.

The misconception, stated plainly: "Both saddles just hold the vessel up. Bolting both of them tight is the safe choice."

It sounds like belt and braces. It is the opposite. A horizontal vessel that changes temperature must change length, and the only question a designer gets to answer is where the growth is allowed to happen. Deny it and the growth does not disappear — it becomes force, and force goes looking for the weakest thing in the chain: the anchor bolts, the base plate, the grout, the shell at the saddle horn.

The correct arrangement is asymmetric on purpose. One saddle is fixed — round holes, bolts torqued, this is the datum from which everything is measured. The other slides — slotted holes, a low-friction plate, nuts snugged then backed off and locked so they retain without clamping. That asymmetry is not a detail left to the fabricator. It is the load path.

Symbol key — every symbol on this sheet

Read the subscripts as words: f = friction, s = seized, slot = the hole, sad = the saddle. The one letter that fights you is μ — here it is only the friction coefficient, never ductility.

Why friction is temperature-blind, and stiffness is not

Two force laws compete at the sliding end, and they are qualitatively different animals.

Friction is a force law with a ceiling. F = μ·W. It does not know how far the vessel travelled. Move 2 mm or 60 mm and the saddle still pushes exactly μ·W into the pier. Its force–travel curve is a short ramp and then a flat line for ever. That is why a working slide is designable: one number covers every operating case, and it is the same in summer and winter.

A seized slide is a stiffness law with no ceiling worth the name. F = k·ΔL. It scales with travel and with how good your foundation is. The absurd consequence: a stiffer, better-built pier produces a larger force when the slide fails. The theoretical ceiling is total axial restraint, F = E·A·α·ΔT, which for a modest 1.2 m × 14 mm shell at 200 °C is 24 000 kN — about 2 400 tonnes. Nothing on the plot plan can take that, which is the real message: the elastic demand is never reached because something breaks on the way. The calculated F_s is what the structure is being asked for, not what it will survive.

This is the same shape of argument as thermal stress in piping: displacement-driven loads are limited by what the system is willing to deform, and the only cheap way to make them small is to let the deformation happen.

Fixed, sliding, and the arithmetic of 15 millimetres

Everything starts at the fixed saddle, because that is the origin of the coordinate system the vessel actually uses:

ΔL      = α · L · ΔT                      growth at the sliding end
F_f     = μ · W                           price of letting it happen
F_s     ≈ k · ΔL   (ceiling E·A·α·ΔT)     price of refusing
L_slot  ≥ 1.25·|ΔL| + d_bolt + erection tolerance

Three consequences fall straight out and are worth holding on to:

Play with the numbers: vessel length, ΔT, material, μ, weight and pier stiffness, with the force–travel plot showing the friction plateau against the seized ramp: ▶ open the interactive: static saddles expansion calc

What makes a slide actually slide. Four details, all of which get lost between the drawing and the field:

Watch the difference: heat the vessel and see the sliding end walk while the fixed end stays put, then toggle Seized slide and watch the force path light up from shell to horn to base plate to bolts to pier: ▶ open the interactive: static saddles expansion 3d

Where the load actually goes — Zick, horns, and skirts

Letting the vessel slide solves the longitudinal problem. It does not solve the local one, because a saddle is a hard point pressed into a thin shell — the same "a shell hates local loads" story as a nozzle, in a different costume.

Zick's logic (L. P. Zick, Welding Journal, 1951; now embedded in ASME VIII-2 Part 4.15 and PD 5500 Annex G) is the industry's answer, and its reasoning is worth knowing even when software does the arithmetic:

Vertical vessels take the other road entirely. A tall column sits on a skirt — a cylinder welded to the bottom head, carrying the vessel down to a base ring, anchor bolts and foundation. The skirt solves differential expansion by sharing it: the skirt is at roughly vessel temperature, grows with the vessel, and there is no relative movement to accommodate. There is no sliding end because there is no second support. Legs and lugs, by contrast, reintroduce exactly the problem saddles have — different metal at a different temperature bolted to a fixed structure.

The skirt's load path is a couple, not a shear:

wind / seismic overturning moment  →  skirt shell (tension one side, compression the other)
                                   →  base ring bearing + anchor bolts in tension
                                   →  foundation and soil
weight                             →  skirt shell in compression  →  base ring  →  concrete
thermal growth                     →  the whole column rises by α·H·ΔT — a nozzle displacement

Three skirt details that cost money when missed: the skirt-to-head weld is the thermal and fatigue hot spot (a steep temperature gradient sits right at a structural discontinuity), which is why hot columns get a hot box — an insulated annulus that stretches the gradient out over a length of skirt instead of concentrating it at the weld. The access opening and vent holes remove material exactly where the overturning couple is highest, so they get reinforced and kept off the neutral-axis-perpendicular. And the fireproofing and its stand-off must not bridge the base ring into a rigid, water-trapping detail.

Worked example — crude preheat exchanger

D = 1200 mm OD, t = 14 mm, carbon steel A516 (α = 12.2 µm/m·°C), L = 6.0 m between saddle centres, operating metal temperature 220 °C above an installation temperature of 20 °C so ΔT = +200 °C. PTFE slide plate, μ = 0.10. Sliding saddle carries W = 150 kN. Saddle + pier lateral stiffness k = 60 kN/mm. Anchor bolts M24.

ΔL      = 12.2e−6 × 6000 × 200                       = 14.6 mm
L_slot  ≥ 1.25 × 14.6 + 24 + 10                      = 52 mm      (so: 55 mm slot, M24)
F_f     = 0.10 × 150                                 = 15 kN      slide working
A       = π × (1200 − 14) × 14                       = 52 162 mm²
ceiling = E·A·α·ΔT = 190 000 × 52 162 × 12.2e−6 × 200 = 24 182 kN  (full restraint — never reached)
F_s     = k·ΔL = 60 × 14.6                           = 878 kN     slide seized
ratio   = 878 / 15                                   = ×58.6
σ_long  = 878 000 / 52 162                           = 16.8 MPa   in the shell — the shell survives

Read the last two lines together, because they are the whole story. The shell shrugs: 17 MPa of longitudinal membrane is nothing. What does not shrug is everything the 878 kN passes through — four M24 bolts in shear, a 34 mm base plate in bending, a grouted pier designed for 15 kN horizontal, and the saddle horn already carrying its Zick circumferential stress. The failure is never in the vessel. It is always in the connection.

Swap the PTFE for bare steel-on-steel (μ = 0.35) and the working force becomes 53 kN — still survivable, but now 3.5× what the foundation drawing says, and on a trajectory toward seizure as it rusts. That is the quiet version of this failure, and it is far more common than the dramatic one.

Common pitfalls

Outcome

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